Could 1FG Stealthers beat 1FG Conventional?

[Matmardigan]

Why not make it 2 fg's of stealthers? just to bu sure :>

-----------O---O---------- mmg/amg
HH -x-----------------------x-
HH ---x-------------------x--- HH
-x---------yyy----------x- HH
HH ---x-------yyy--------x--- HH
HH -x----------------------x- HH
HHHHHHHH

x = hunters(rr 5+ with bc 32)
y = shadowblades(rr 5+ and at least one with mezz-poison)
H = Hibs
All attack at the same time(using ventilo ofc).

I doubt any fg would survive this.

u 4get the 3fg hibs which will pop behind u suddenly

 

[[e]]

it's highly possible. But "possible" is not = "easy"
Would be very cool to try and have some challenge in the fight, rather then the standard zerg/leech/add4tehwin. I don't know what kind of imagination you guys have, but in my mental picture of this event, I dont see the scouts lined up like rps cows. With the range they can pretty much spread out to the extent that 1 instant AOE mezz/stun = 1 scout disabled. Heard of purge?

The main problem is all the instants that healers have. The win or loose factor is if healers can be disabled from using their skills long enough to kill them thus giving stealth grp advantage in numbers. If fight can be made 5 vs 8 very quickly, and stealthers are spread out, the mid tankgrp will have serious problems. With the MLs and TOA set, the scouts wont be killed that easy, and no matter who they target, there will always be ppl without aggro doing massive dmg from range. Tbh, with a good grp, lots of teamwork practice and voicecom, I cant see any reason why this should not work. And btw, a minstel cant mezz from behind a grp? The mezz just have to last a few sec anyway - long enough for stun and zephur. Maybe switch a scout for another minstel? 2 x stun, 2 x zehpur ....

I don't know...there are many different ways/setups to try this. The point is, I would love to see the effort!

 

[Asha]

you do know you dont have to stand infront of them unstealthed casting while they run towards you?
I am _very_ sure any decent mincer can manage an aoe-mezz against most mid groups.

If you're behind them, unless they are standing stock still in a very very small area, and afk, you should not get it off.

hokeeyy, your assuming a healer resists his stun? lets just assume that the stealthgroup resists everything and the enemy tanks miss on everything they do. the stun is decent lvl in instruments so its not resisted more often than not, hence i can assume that it wont be resisted.

no, but it only takes one healer of three to either react before mez is cast, resist, or purge.

put one scout on him then, or mincer can dd him till scouts drop their first two targets.

err he could just insta the mincer or the scout for that matter - ofc he could stand there going wtf??? too

i like how you exaggerate the stuff i say. I "used" the following ra's: ap3, ip. (and maybe a sos in the end if the mincer wanna live )

well by stuff I meant artis and mlvl abilities and ras and etc... you seem to leave out things like CB and purge and the fact that 3 healers are very likely to have 3 zephers...

Or hunter vs a fg like fatbelly said. On paper its nigh impossible, but he managed didnt he?

FB against some noobs isn't really what we were discussing ^^

I agree that it's POSSIBLE - but imo only if the normal group is either asleep or just making huge mistakes.

(and roflmao at your smileys, i got the following message when i tried to post: "You have included too many images in your signature or in your previous post. Please go back and correct the problem and then continue again." such a smiley abuser tbh xD )

ofc ! I get that msg with almost every post
It's just I was trying to make a point but not offend ex-teddy bears

 

[Theseus]

From a realistic, ranger's point of view. The chance that 1 caster gets lose and kills 2 scouts in 8seconds is very big. Or maybe a healer can insta himself just the right time and a tank gets lose and goes and slam 2 scouts...

In theory a stealthgrp that knows eachother well and has an average off rr5+ should be able to kill a fg off semi-high rr's with an average off rr4l5.
We (Post Mortem) has done it recently (2 weeks ago) while camping amg but we did lose 1 NS as the rangers were on the walls and pretty safe but the NS's get all the blows.

This works if you got mezzpoison plus 3 or more GS lvl 10 users to interrupt everyone.
You can use all the tactics you want ...it will not work out as you planned cuz you dont know what the grp can do.

The key is keep the grp interrupted after mezz so casters and healers are only 40% effective and ofc assist

 

[Appollo]

Me, Meduza and Elajt once killed a full-group of mids. Low rr of course, but was great fun. What we did was I was sitting on AMG Odin's, and I killed their Shamen with critshot, normal, normal, etc. dead. I then attacked their Healer. Meanwhile the rest of their group blundered up the stairs to get me while Elajt and Meduza finished off my healer and killed the second one. I stuck my ass into a corner and the mids, now unbuffed, couldn't do much damage through my shield and evade. Elajt and Meduza came upstairs and killed them.

Also once at amg Odin's I was waiting for Meduza to port and a fg hibs came along. Waucan told every stealther at amg to jump them, and they went down pretty much instantly. May well have been more than a fg of stealthers at amg though.

But for the most part it can't be done. Stealthers get no heals, are particularly vulnrable to cc and a few shield tanks standing in the right direction will negate the advantage of any archers.

that was fun

 

[Ralgedi Smurf]

Not 100% stealth but could be fun, Hide a sorc in amg/mmg room wait for a fg to pass. mezz em all str/con debuff and 7 scouts to assist each other, 2 scouts on every healer and 1+sorc on shammy

after all support is death, stealth point laugh etc

 

[Meduza]

that was fun

Agree.

We did it 2 times tho to that grp. 3rd time they got us (but only becuz we fumbled ofc! )

 

[popa]

yes , but i say only albs can make that
DL the movie too see it http://www.mogamers.net/forums/index.php?download=128