0.999999 recurring actually equals 1

[Bugz]

lim_(m --> oo) sum_(n = 1)^m (9)/(10^n) = 1

0.9999... = 1

Thus x = 0.9999...
10x = 9.9999...
10x - x = 9.9999... - 0.9999...
9x = 9
x = 1.

Fascinating don't ya think!

 

[CorNokZ]

no and it's not true


0.999... will never equal one! It wil be close, but never equal

 

[tris-]

lim_(m --> oo) sum_(n = 1)^m (9)/(10^n) = 1

0.9999... = 1

Thus x = 0.9999...
10x = 9.9999...
10x - x = 9.9999... - 0.9999...
9x = 9
x = 1.

Fascinating don't ya think!

Pretty basic algebra but it does show something worthwhile I suppose

 

[Chronictank]

lim_(m --> oo) sum_(n = 1)^m (9)/(10^n) = 1

0.9999... = 1

Thus x = 0.9999...
10x = 9.9999...
10x - x = 9.9999... - 0.9999...
9x = 9
x = 1.

Fascinating don't ya think!

er my maths is a little rusty but isn't this is wrong;
10x = 9.9999...

I think it is suppose to be

10x= 8.991

 

[Bugz]

9.9999 - 0.9999 is 9

 

[Chronictank]

edited above, i think there was something about the multiply and the minus,
it is as close to one as possible but you cannot just substract it as it is a infidecimal

 

[Lethul]

Cornokz is right tho lim towards infinity never reaches "equal".
So

0.9999... = 1 actually is 0.9999... != 1

 

[Bugz]

How Can 0.999... = 1?

As long as it is 0.9 recurring, then 0.9 recurring and 1 are the same 'real' number.

 

[Chronictank]

its not the same afaik, it equals 1 (based on limit theory) AND .9999 but not 1 exclusively

or something along those lines

I may be wrong tho

 

[Bugz]

It's certainly interesting none-the-less!

 

[Chronictank]

This question makes by brain hurt ><

Rep for bringing it up tho, after some reading i am a convert
if you multiply both sides .999 does (i think) equal 9/9

 

[fl3a]

proving that 0.9999999999 infinitely recurring is the same as 1 is kind of like proving that 3 is 3, if you understand the mechanics behind it. what makes people think its weird is that its normally presented in the way bugz showed it and they cant grasp that in 0.9999... the ... means an infinite amount of 9's afterwards

 

[Access Denied]

This makes my head hurt =( Never was fantastic at Maths. Multiplicaion division (Not long) subtraction Adding and volume are all I can do =P

 

[- English -]

saying 0.9999 = 1 is like saying 2 paralell lines will meet ;<

 

[Chronictank]

saying 0.9999 = 1 is like saying 2 paralell lines will meet ;<

it's not

 

[Sparx]

infidecimal

 

[fl3a]

saying 0.9999 = 1 is like saying 2 paralell lines will meet ;<

noone is saying that, they are saing that 0.99999999999999999999(and so on with the nines) = 1, which is true in a sense

 

[- English -]

noone is saying that, they are saing that 0.99999999999999999999(and so on with the nines) = 1, which is true in a sense

not in my straight forward thinking sense... its 0.99999, to make it to 1 you would need to add something 000000.1( however many 9's). Without adding, how can it become 1.

Someone needs to put it into an English explaniation ;p

 

[Bugz]

But 0.9999 recurring you'd have to add 0 to get to 1 in a simplistic sense, as the 9's never end.

So you say it's 1.

 

[Elvo^Rylu]

<waves at English>

As said earlier, it's because your trying to replace infinitesimal numbers with decimals.

x = 1 - 1/oo
10x = 10 - 10/oo
10x - x = 10 - 10/oo - (1 - 1/oo)
9x = 9 - 9/oo
x = 1 - 1/oo

In your equation your making the assumption that 1-1/oo = 1.

If you were to do it the way you did it, then you would have to choose a limited number, like 0.9999....9, so that 10*x= 0.9999....0. This will lead to 9.9999....0 - 0.9999....9 = 8.9999....1 and so forth.

 

[gohan]

of its not the same thats completly flawed maths lol.... thier doing 0.9999

that 4 decimle places and not recuring



0.9999 x 10 = 9.999

- .9999
= 8.9991


not 9

so its totaly flawed, thier basicly choseing how many decimle places to use each time to prove thier theory, i mean FFS i gave up maths after AS level and i clicked on that instantly

 

[gohan]

and it may be more convinent to say 0.999 recurring is 1

but its isnt

or it would be 1 not 0.999 recurring


OBVIOUS FUCKING LEEEEEEEEEEEEEE

 

[gohan]

But 0.9999 recurring you'd have to add 0 to get to 1 in a simplistic sense, as the 9's never end.

So you say it's 1.

again




NO




0.99999999999999999999999999 + 0



surisingly still = 0.9999999999999999999999999


you'd need and infinate number of .0's folled by a 1, but it can't happen u can only make 0.9 recurring into a whole by multiplying it by whateva number dived it into 0.9999 to begin with

 

[Bugz]

0.999... - Wikipedia, the free encyclopedia

Stop trying to argue with people who dedicate their whole lifes to studying maths lol.

 

[Bugz]

FFS i gave up maths after AS level and i clicked on that instantly

Well that says it all really

 

[gohan]

well your the retard that thinks 0.9999999999999 =1 when clearly it doesn't or i would be called one



fucking arrogant little prick

 

[Bahumat]

Haha I agree with Gohan

Also I wouldn't want to be caught down an alley by Ghona with just a calculator in my pants!

 

[Bugz]

Have you looked at ANY of the links? Some of the proofs are uni-level. How can you criticise them when you dropped maths at AS?

How can you make a claim that something isn't the case using only the most basic of algebra, when there are a lot of proofs to show it & a lot of mathematicians who believe so?

As for being arrogant, I don't see how I conveyed that but believe as you like

 

[Chronictank]

well your the retard that thinks 0.9999999999999 =1 when clearly it doesn't or i would be called one



fucking arrogant little prick

You mean 0.9999999999999...
or 9/oo (infinity)


.9 (add as many as you like) as a complete number is not the same as 9 to the infinity

 

[Bahumat]

<waves at English>

Lets REP PL this guy!